Question

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Answer 1

option A

hope it may helps you

Answer 2

$\huge\boxed {Answer}$

Resistance

Firstly , 2 ohm & 2 ohm are in series .

So , R = 2 + 2

R = 4 ohm

Next , 4 ohm & 2 ohm are in parallel

So , Effective Resistance (R) = 4×2 / (4 + 2)

R = 8/6 = 4/3 Ohm

Therefore

Current flows in this figure

I = V/R

= 2/(4/3)

= 6/4

= 1.5 A (ऐम्पियर)