Question

please try to solve this problem!!
note: no spams here!!
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Answer 1

$\rm\dfrac{y-1}{3}-\dfrac{y-2}{4} = 1$

First we will make the denominators equal.

If we multiply any number in the denominator, the same we will have to multiply in the numerator, so that the value of the fraction remains same.

$\rm\dashrightarrow\dfrac{4(y-1)}{4(3)}- \dfrac{3(y-2)}{3(4)} = 1$

$\rm\dashrightarrow\dfrac{4y-4}{12}- \dfrac{3y-6}{12} = 1$

Now since, both the fraction have same denominator, therefore we can perform our Operations on numerators now.

$\rm\dashrightarrow\dfrac{4y-4-(3y-6)}{12} = 1$

$\rm\dashrightarrow\dfrac{4y-4-3y+6}{12} = 1$

$\rm\dashrightarrow\dfrac{4y-3y-4+6}{12} = 1$

$\rm\dashrightarrow\dfrac{y+2}{12} = 1$

$\rm\dashrightarrow y+2 = 1 \times 12$

$\rm\dashrightarrow y+2 = 12$

$\rm\dashrightarrow y=12-2$

$\rm\dashrightarrow y=10$

Hence, the value of y is 10

Answer 2

The value of y is 10 .

This is your answer. It will help you.