Question

PLEASE TRY TO SOLVE THIS QUESTIONS.​

Answer 1

Let the point dividing the line segment joining points A(-2, 6) and B(3, -4) in the ratio 2 : 3 be (X, Y).

m : n = 2 : 3 => m = 2 and n = 3

$(x_{1}, y_{1}) = (-2, 6) \\ (x_{2}, y_{2}) = (3, -4)$

$(X, Y) \\ = (\frac{mx_{2} + nx_{1}}{m + n}, \frac{my_{2} + ny_{1}}{m + n}) \: \: \: \: \: \: ... (section \: formula) \\ = (\frac{(2)(3) + (3)(-2)}{2 + 3}, \frac{(2)(-4) + (3)(6)}{2 + 3} \\ = (\frac{0}{5}, \frac{10}{5}) \\ = (0, 2) \\ \\ (X, Y) = (0, 2)$

since the line we're supposed to find equation of has gradient (m) = 3 and passes through (X, Y) = (0, 2)

using slope point formula, equation of the line is–

y - Y = m(x - X)

y - 2 = 3(x - 0)

y - 2 = 3x

3x - y + 2 = 0

Hence, equation of the line is 3x - y + 2 = 0

Answer 2

Answer:

in which class you sdudies