Question

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Answer 1

✪ Answer ✪

Complex number in the form r(cos $\beta$ + isin$\beta$) can be written as r$e^{i\beta$.

Here:

• β is the argument
• i represents iota
• r is the magnitude of the complex number

Thus, $e^{2+i$ can also be written as $(e^{2})(e^i)$

Now, $e^i$ = cos 1 + isin 1

This is because $e^i$ has amplitude 1 and also the magnitude 1.

Hence, $e^{2+i$ = $(e^2)e^i$ = $e^2$ (cos 1 + isin 1)

✰      Your answer will be option B    ✰