Please try to tell how this happens angle OBA = 90-(theta/2)
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Here angle of linaer line is 180'
so angle(TBV+XBF+OBA)=180'
then, 90'+(theta÷2)+x=180'=) theta÷2+X=180-90
angleOBA=90-theta÷2
so angle(TBV+XBF+OBA)=180'
then, 90'+(theta÷2)+x=180'=) theta÷2+X=180-90
angleOBA=90-theta÷2
Answered by
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Hey there !
Thanks for the question !
Answer:
Consider the ray AF.
Now it is a straight line. So, the angle made by a straight line is 180°.
So we can say that,
∠ OBA + ∠ OBX + ∠ XBF = 180°
Given that, ∠ OBX = 90° ; ∠ XBF = ( Ф / 2 )°
So Substituting them in the equation 1, we get,
∠ OBA + 90° + ( Ф / 2 )° = 180°
=> ∠ OBA = 180° - 90° - ( Ф / 2 )°
=> ∠ OBA = 90° - ( Ф / 2 )°
Hence we arrive at the solution that, ∠ OBA = 90 - ( Ф / 2 )°.
Hope my answer helped !
Steph0303:
:)
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