Question

please try to tell the answer fast​

Answer 1

Answer:

5

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Answer 2

Answer:

${x}^{2} -5x+1=0$

${x}^{2} =5x-1$

${x}^{2} + \frac{1}{ {x}^{2} }$

$= 5x - 1 + \frac{1}{5x - 1}$

$= \frac{ {(5x - 1)}^{2} + 1}{5x - 1}$

$= \frac{25 {x}^{2} - 10x + 1 + 1}{5x - 1}$

$= \frac{25 {x}^{2} - 10x + 2}{5x - 1}$