Question

Please understand the code and explain why the value of variable "b" printed is not 'W'.
void foo(void) {
char array[8];
char b= 'W';
memset(array, 0,8);
for (int i = 0; i<=8; i++)
array[i] = i +48;
printf("%c", b);​

Answer 1

Answer:

dont know the answer bro