Question

please upload with solve.

Answer 1

Hey, I've used Componendo-Dividendo.
If u don't know comment....

BTW, answer is (2) i. e. 12/5

Answer 2

$\mathbb{ANSWER}$ : Option 2 ( 12/5)

$\mathcal{ \: \: EXPLANATION}$ :

$\frac{\sqrt{3 + x} + \sqrt{3 - x} }{ \sqrt{3 + x} - \sqrt{3 - x} } = \frac{2}{1}$

Apply componendo and dividendo.

$\frac{(\sqrt{3 + x} + \sqrt{3 - x}) + ( \sqrt{3 + x} - \sqrt{3 - x} )} {(\sqrt{3 + x} + \sqrt{3 - x}) - (\sqrt{3 + x} - \sqrt{3 - x})}= \frac{2 + 1}{2 - 1} \\ \\ \frac{ 2( \sqrt{3 + x} )}{2 (\sqrt{3 - x} )} = 3 \\ \\ \frac{3 + x}{3 - x} = 9 \\ \\ 3 + x = 9(3 - x) \\ \\ 3 + x = 27 - 9x \\ \\ 10x = 24 \\ \\ x = 2.4$

Therefore, x = 12/5