Please use the following balanced chemical equation to answer the following questions: Fe2O3 (s) + 3CO(g) ------> 2Fe(s) + 3CO2 (g)
How many grams of Fe(s) could you produce given 2.45 moles of Fe2O3(s). Assume an excess of CO(g)
How many grams of Fe(s) could you produce given 1.50 grams of Fe2O3 (s). Assume an excess of CO(g)
What is the volume of CO2 (g) you could produce given 25.0 grams of Fe2O3 (s). Assume an excess of CO(g).
How many molecules of CO2 (g) could you produce given 45.5 grams of Fe2O3 (s). Assume an excess of CO(g).
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Answer:
1.3
Explanation:
The atomic masses of C and O are 12 g/mol and 16 g/mol respectively.
The molar mass of CO is 12+16=28 g/mol.
56 g CO corresponds to
28
56
=2 moles.
As per balanced chemical equation, 1 mole of Fe
2
O
3
will react with 3 moles of CO.
Hence, 3.0 moles of Fe
2
O
3
will react with 3.0×3=9 moles of CO.
However only 2 moles of CO are present. Hence, CO is the limiting reagent and Fe
2
O
3
is excess reagent.
As per the balanced chemical equation, 3 moles of CO produces 2 moles of Fe.
Hence, 2 moles of CO will produce 2×
3
2
=1.3 moles of Fe.
i hope it is helpful for u
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