Question

Please who know only they will give solution.If don't know please don't give wrong solutions. question no. 4 .please give right solution. I will make your answer as a brain list answer. BUT THE ONLY CONDITION IS GIVE WRITE SOLUTION AND ANSWER. THANK Ü.

Answer 1

Hi guys ☺,
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(this answer helps me to forget you Ayushi)
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Here is your answer,
The answers is in Attachment.
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(ignore my grammatical mistakes...)
hope it helps... comment on it...if you like Mark it brainlest for earning free 3 points.

Answer 2

let p(x)=2x^4-5x^3+2x^2-x+2

first will factorise x^2-3x+2 by using by middle term splitting

=x^2-3x+2

=x^2+((-2)+(-1))x+2

=x^2-x-2x+2

=x(x-1)-2(x-1)

=(x-2)(x-1)

As (x-2)(x-1) = x^2-3x+2

Now, let (x-a)=(x-2)

let (x-b)=(x-1)

as x-a =0

x=2

p(2)=2(2)^4-5(2)^3+2(2)^2-(2)+2

       =32-40+8-2+2

       =-42+42

       =0

as x-b = 0

x=1

p(1)=2(1)^4-5(1)^3+2(1)^2-(1)+2

       =2-5+2-1+2

       =-6+6

       =0

as we are getting 0 after putting x=1 and x=2

hence x-1 and x-2 are factors of p(x)

as (x-2)(x-1)=x^2-3x+2

hence x^2-3x+2 is a factor of p(x)