Question

please with explanation​

Answer 1

${\huge{\bold{\underline{Answer}}}}$

given

area of circle =154 cm ²

πr² = 154

$\frac{22}{7} \times {r}^{2} = 154 \\ {r}^{2} = \frac{154 \times 7}{22} \\ {r}^{2} = 49 \\ r \: = \sqrt{49} \\ r \: = 7 \\ hence \: radius \: is \: 7 \: cm \\ \\ so \\ circumference \: = 2\pi \: r \\ 2 \times \frac{22}{7} \times 7 \\ = 44 {cm}^{ ^{2} }$

1. 2) X ² = monomial
2. a+b-c = trinomial
3. 2x+4 = binomial
4. a²+2a = binomial

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Answer 2

Answer:

E/

$area \: of \: the \: circle = \pi {r}^{2}$

$\frac{22}{7} \times {r}^{2} = 154 \\ r = 7cm$

Circumference of the circle = 2πr

$= 2 \times \frac{22}{7} \times 7 = 44cm$

2.

$( a){x}^{2} = monomial$

(b) a+b-c=trinomial

(c) 2x+4=binomial

(d)

${a}^{2} + 2a = binomial$

3.(2 {x}^{2} - 2y + 2z) +( 2 {x}^{2} + 3y + 4z)

=2 {x}^{2} - 2y + 2z + 2 {x}^{2} + 3y + 4z

=2 {x}^{2} + 2 {x}^{2} - 2y + 3y + 2z + 4z

=4 {x}^{2} + y + 6z