Question

please with steps guys​

Answer 1

Answer:

$i)3 {}^{ - 2} = 1 \div (3 {}^{2} ) = 1 \div 9$

$ii)( - 4) {}^{ - 2} = 1 \div ( - 4) {}^{2} = 1 \div ( - 16) = - 1 \div 16 \\ iii) {9}^{0} = 1 \: as \: anything \: power \: zero \: is \: one \: (1)$