Question

PLEASE WRITE Ans
Factorise 2x² + 7x + 3.​

Answer 1

$\large{\boxed{\boxed{\sf{QUESTION}}}}$

Factorise 2x² + 7x + 3

$\large{\boxed{\boxed{\sf{REQUIRED \: ANSWER -}}}}$

$\red{\bigstar}$ 2x² + 7x + 3 $\large\leadsto{\tt\purple{[ 2x + 1 ] [ x + 3 ]}}$

$\large{\boxed{\boxed{\sf{ACCORDING \: TO \: THE \: QUESTION - }}}}$

if we want to factorise 2x² + 7x + 3 then we need to split the middle term to get factors such that their sum is middle term .

• so the two terms are 1x or we can x and 6x

Because-

• the sum of 1x and 6x is 7x
• their product is 6x² [ 2x² × 3 ]

Now we know that -

➪ 2x² + 7x + 3

➪ 2x² + 6x + 1x + 3

now now we will take 2x and 1 common

Therefore ,

➪ 2x [ x + 3 ] + 1 [ x + 3 ]

now now we will take x + 3 common

Therefore ,

➪ [ 2x + 1 ] [ x + 3 ]

_____________

Confused ?! Nevermind let's check our answer

➪ [ 2x + 1 ] [ x + 3 ]

first we will multiply 2x by x + 3 then + 1 by x + 3

➪ 2x [ x + 3 ] + 1 [ x + 3 ]

➪ 2x² + 6x + 1x or x + 3

➪ 2x² + 7x + 3

now you can see that after solving [ 2x + 1 ] [ x + 3 ] we got 2x² + 7x + 3

★ hence proved