Question

please write answer and explain the answer ​

Answer 1

$LHS = \frac{ (6a-5b)^{2} - (6a+5b)^{2} }{ab}$

/* By algebraic identity */

$\boxed{\pink{ (x-y)^{2}-(x+y)^{2} = -4xy }}$

$= \frac{ - 4 \times 6a \times 5b }{ab}$

$= \frac{ - 120ab }{ab}$

$= - 120$

$= RHS$

•••♪