Question

PLEASE WRITE CORRECT ANSWER THIS IS IMPORTANT!!


A 1,000kg moving with a speed of 20 m/s is brought to rest in a distance of 50 m, (i)Find the acceleration (a= - 4 m/s^2).
(ii)Calculate the unbalanced force acting on the vehicle (F= - 4,000 N)
PLEASE DONT WRITE FALSE ANSWER Please!!

Answer 1

F= 1000kg

u= 20m/s

v= 0m/s

s= 50m

1st part

we know that

$v^{2} - u^{2} = 2as$

so,

a= $v^{2} - u^{2} /2a$

a=(0-20×20)/(2×50)

a= -4$m/ s^{2}$

2nd part

we know that 

F = ma  

m = 1000kg

a = 4 m/$s^{2}$

so, 

F= 1000×-4

F = -4000N