Math, asked by mirzazafar2321, 4 months ago

please write in full prosess please...​

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Answered by swamyg79494
2

Answer:

 ({ {2}^{  - 5} })^{2}  \times ({ {2}^{  - 5} })^{ - 2}  \times ({ {2}^{ - 7 } })^{ - 2}  \times ({ {2}^{ - 7 } })^{2}  \\(  {( {a}^{m} })^{n} =  {a}^{m \times n}  ) \\  {2}^{ - 10}  \times  {2}^{10}  \times  {2}^{14}  \times  {2}^{ - 14}  \\ ( {a}^{m}  \times  {a}^{n}  =  {a}^{m + n} ) \\ by \: using \: above \: formula \\ ( {2})^{ - 10 + 10}  \times  ({2})^{14 - 14} \\  ({a}^{0}   = 1) \\ 1  \times 1 = 1 \\ hope \: it \: helps \: u \: :)

Answered by hasanjamey
1

Answer: hope I help you...

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