Question

please write step by step answers​

Answer 1

Answer:

ANSWER OF THIS QUESTION PLEASE SEE THIS IS THE CORRECT ANSWER

Explanation:

Highest frequency 12 , Modal class =40−60

Mode =I+2f1−f0−f2f1−f0×h

Where ,

I= lower limit of the modal class =40

f1= frequency of modal class =12

f2 frequency of class after the modal class =6

f0 frequency of class before the modal class =10

h= class width =20

putting the values in the equation 

Mode=50

Hope it helps you .

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Answer 2

Answer:

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