Physics, asked by KamilSinghThakur, 19 days ago

please write the answer.​

Attachments:

Answers

Answered by vikkiain
1

Use, A.B = |A|  |B| cos \theta

Explanation:

Given,  \:  \: A = 2i + j + 2k \:  \: and \:  \: B = 2i  - 2 j  - k \\ Now, \:  \:  \: A.B \:  = (2i + j + 2k).(2i  - 2 j  - k) \\  = 2 \times 2 + 1 \times  - 2 + 2 \times  - 1 \\  = 4 - 2 - 2 = 0  \\ Then, \:  \: A.B  = |A|  |B| cos \theta = 0 \\ cos \theta = 0 \\ \theta =  \frac{\pi}{2} \\ so \: \: \: A \: \: and \: \: B \: \: are \: \: perpendicular

Similar questions