Question

Please yaar please help me ​

Answer 1

Answer:

a=√3+1/√3-1

b=√3-1/√3+1

a^2=(√3+1)^2/(√3-1)^2

=(3+1+2√3)/(3+1-2√3)

=(4+2√3)/(4-2√3)

=2(2+√3)/2(2-√3)

=(2+√3)/(2-√3)

=(2+√3)^2/(2+√3)(2-√3)

=(4+3+4√3)/4-3

=7+4√3

b^2=(√3-1)^2/(√3+1)^2

=(3+1-2√3)/(3+1+2√3)

=(4-2√3)/(4+2√3)

=2(2-√3)/2(2+√3)

=(2-√3)/(2+√3)

=(2-√3)^2/(2+√3)(2-√3)

=(4+3-4√3)/(4-3)

=7-4√3

ab=(√3+1)/(√3-1).(√3-1)/(√3+1)=1

a^2+ab-b^2

=(7+4√3)+1-(7-4√3)

=7+4√3+1-7+4√3

=8√3+1

Answer 2

Answer:

good mornig my dear friend

how are you

and where do you live

and kya aap ins.ta par ho