Question

Please yaar please help me

Answer 1

Step-by-step explanation:

$i) \: \: \: \: \: \: \: (1 - {x}^{2} )(1 - {y}^{2} ) + 4xy = 1 - ( {x}^{2} + {y}^{2} - 4xy) \\ = {1}^{2} - {(x + y)}^{2} \\ = (1 - x - y)(1 + x + y) \\ \\ \\ ii) \: \: \: \: \: \: \: \: \: \: {c}^{2} + 2ab - ( {a}^{2} + {b}^{2} ) \\ = {c}^{2} - ( {a}^{2} + {b}^{2} - 2ab) \\ = {c}^{2} - {(a + b)}^{2} \\ = (c - a - b)(c + a + b) \\ \\ \\ \\ \\ iii) \: \: \: \: \: \: \: \: \: p - 2q - {p}^{2} + 4 {q}^{2} \\ = (p - 2q) - ( {p}^{2} - 4 {q}^{2} ) \\ \\ = (p - 2q) - ( {p}^{2} - {(2q)}^{2} ) \\ \\ = (p - 2q) - (p - 2q)(p + 2q) \\ \\ = (p - 2q)(1 - p - 2q)$

$iv) \: \: \: \: \: \: \: \: \: {b}^{2} + {c}^{2} + 2(ab + bc + ca) \\ \\ = {(b + c)}^{2} + ba+ ac \\ \\ = {(b + c)}^{2} + a(b + c) \\ \\ = (b + c)(b + c + a)$

Answer 2

Answer:

soni yaar kabhi baat bhi kar liya karo