Question

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Answer 1

Answer:

given the series [-4+(-1) +2+.... +x=437]

in A.P

Then, a=-4

d= -1-(-4) =3

Sn=437

Then, using sum formula A.P.

Sn=n/2[2a+(n-1) d]

=> 437=n/2[2(-4) +(n-1) 3]

=> 874=3n²-11n

=> 3n²-11n=874

=> 3n²-11n-874=0

=>3n²-(57-46) n-874=0

=> (n-19) (3n-19) =0

=> n-19=0

=> 3n-19=0

=> n=19/3

=> so,

=> x=a+(n-1) d

=> x= -4+54

x=50,

Hence, this is the answer