please ye question bta do ki
Answers
Answer:
let the no. of rs 5 coins be x
& the no. of rs 1 coin be y
& no. of rs 2 coins be 3 x
a.q.t total no. of coins = 160
x + 3x+y = 160
4x + y = 160 eq. 1
again a.q.t total rs = 300
5x + 2(3x) + 1y = 300
11x + y = 300 eq. 2
by elimination method
on subtracting both the equations
4x + y = 160
-11x -y = -300
=-7x =-140
x =20
on putting the the value of x in eq 2
4(20) + y =160
80 + y = 160
y =80
now,
no of rs 2 coins = 3(20)
= 60
no. of rs 5 coins = 20
no. of rs 1 coins=80
or
Let the no. of Rs. 5 coins be x
no of Rs. 2 will be 3x
Rs. 1 coin be. 160-3x-x = 160-4x
the amount I have,
from Rs. 2 coins= 3x= 3x2 = 6x
from Rs. 5 coins= x= 5x
from Rs. 1 coin = (160-4x)x1 = 160-4x
Total money Rs.300
6x+5x+160-4x = 300
7x + 160 = 300
7x = 140
x = 20
No. of Rs. 2 Coins = 3x20= 60
No. of Rs. 5 coins = x=20
No. of Re. 1 coin = 160-4x20 =80
And That's The answer !!