Question

please you have me answer all question ​

Answer 1

They are questions about calculations. (mostly)

A rectangular sheet of paper will have two sides 12 1/2 cm and 10 2/3 cm long.

Solution: To find a perimeter multiply by 2 and add them.

2(12 + 1/2) + 2(10 + 2/3) = 24 + 1 + 20 + 4/3 = 45 4/3 = 46 1/3 cm

Answer: Therefore, the perimeter is 46 1/3 cm long.

The triangle has three sides 5/2 cm, 3 3/5 cm, 2 3/4 cm long.

Solution: Its perimeter is 5/2 + 3 3/5 + 2 3/4 cm.

The lcm of denominators is 20.

50/20 + 3 + 12/20 + 2 + 15/20 = 5 77/20 = 8 17/20 cm (triangle)

Solution: 2(2 + 3/4) + 2 × 7/6 is the other perimeter.

4 + 3/2 + 7/3 = 4 + 9/6 + 14/6 = 4 23/6 = 7 5/6 cm (rectangle)

Answer: Now the perimeter of the triangle is definitely greater.

The frame can hold a picture of 7 3/10 cm² wide. But the picture is 7 3/5 cm².

Solution: The picture is wider so the area should be subtracted.

7 3/5 - 7 3/10 = 3/5 - 3/10 = 3/10 cm²

Answer: The picture should be trimmed as 3/10 cm² wide.