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1 is 90* plus the both no. it is so easy
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Ans 1. In ΔADC
tan30
o
=
AC
DC
3
1
=
d
h
........(1)
d=
3
h
→d=
3
×10
3
=30m
In ΔBCD
tan60
o
=
BC
DC
3
=
d−20
h
.......(2)
on solving equation (1) & (2)
3
=
3
h−20
h
⇒3h−20
3
=h
2h=20
3
h=10
3
m
height of tower.
Ans 2. For Ans 2. REFER TO THE ATTACHMENT
Ans 3. REFER TO ATTACHMENT
Ans 4. REFER TO THE ATTACHMENT
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