Question

pleased tell correct answer only​

Answer 1

Answer:

8m

Step-by-step explanation:

distance of ladder from foot=√(10²-6²)=8m

Answer 2

Given:

• Length of ladder = 10 m
• Hieght of wall = 6 m

To find:

• Distance of foot of ladder from wall = ?

Solution:

If we visualize the situation we can see a right - angled triangle !

There's a wall 6 m high and a ladder standing with the help of wall and making a right - angled triangle. If we analyze the situation the hypotenuse of the triangle BC be 10 m and the hight of triangle AB be 6 m. We have to calculate the the base of the triangle i.e, AC.

Just apply the Pythagoras theorem !

==> (BC)^2 = (AB)^2 + (AC)^2

==> (BC)^2 - (AB)^2 = (AC)^2

(put the values)...

$= = > \: {10}^{2} - \: {6}^{2} \: = {ac \: }^{2}$

$= = > 100 \: - \: 36 \: = \: {ac \: }^{2}$

$= = > \: \sqrt{64} = \: ac$

==> 8 m = AC

Hence, the distance between the foot of ladder from the wall is 8 meters.

Hope it helped you dear...