Question

Pleased tell me answer of this question. ​

Answer 1

Step-by-step explanation:

Area of school playground is 160 m × 80 m = 12800 m2 Area kept for swings = 80 m × 80 m = 6400 m2 Area of path parallel to the width of playground = 80 m × 1.5 m = 120 m2 Area of path parallel to the remaining length of playground = 80 m × 1.5 m = 120 m2. Area common to both paths = 1.5 m × 1.5 m = 2.25 m2. [since it is taken twice for measuerment it is to be subtracted from the area of paths] Total area covered by both the paths = (120 + 120 – 2.25) m2 = 237.75 m2. Area covered by grass = Area of school playground – (Area kept for swings + Area covered by paths) = 12800 m2 – [ 6400 + 237.75] m2 = (12800 – 6637.75) m2 = 6162.25 m2.Read more on Sarthaks.com - https://www.sarthaks.com/840468/nursery-school-play-ground-160-long-and-wide-is-kept-for-swings-and-in-the-remaining-portion