Math, asked by luckysingh69, 1 year ago

PLEASEEE ANSWER FAST Question no 4 ​

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Answered by arusha8683
13

Let a be any positive integer

b=3

Then, a= 3q+r for some integer q≥0

r= 0,1,2 because 0≤r<3

Therefore,

a=3q or 3q+r or 3q+2

or

a² = (3q)² or (3q+1)² or (3q+2)²

a² = (9q ²) or (9q²+6q+1) or ( 9q²+12q+4)

= 3 × 3q² or 3(3q² +2q)+1 or 3(3q²+4q+1) +1

= 3m or 3m+1 or 3m+2 ( let 3q²=m, 3q²+2q=m, 3q²+4q+1=m)

Hence, it can be said that the square of any positive integer.

Answered by Anonymous
10

Answer:

Let us consider an arbitrary positive integer as ' x ' such that it is of the form 3q , ( 3q+1 ) , ( 3q+2 ).

Solution is in the Attachment.

Hope it will be helpful.⚔️

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