pleaseee answer. these 29 and 30
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29) slope of VT graph = acceleration
5÷1 = 5 ms^-2
30) total area = distance = 175
displacement= +25-150
= -125
5÷1 = 5 ms^-2
30) total area = distance = 175
displacement= +25-150
= -125
ratti:
please answer the question 30
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