Question

pleaseeee answer this asap​

Answer 1

Step-by-step explanation:

clearly option d is irrational

Answer 2

Explanation:

In option a,

$\mathsf{\frac{\sqrt12}{\sqrt3}=\frac{\sqrt{2\times2\times3}}{\sqrt3}=\frac{2\sqrt3}{\sqrt3}=2}$

Hence, option a is not irrational.

In option b,

$\mathsf{\frac{\sqrt18}{\sqrt2}=\frac{\sqrt{2\times3\times3}}{\sqrt2}=\frac{3\sqrt2}{\sqrt2}=3}$

Hence, option b is not the correct option either.

In option c,

$\mathsf{\frac{\sqrt45}{\sqrt5}=\frac{\sqrt{3\times3\times5}}{\sqrt5}=\frac{3\sqrt5}{\sqrt5}=3}$

Therefore, option c is yet again, not the correct option.

However, in option d,

$\mathsf{\frac{\sqrt42}{\sqrt7}=\frac{\sqrt{6\times7}}{\sqrt7}=\frac{\sqrt6\times\sqrt7}{\sqrt7}=\sqrt6}$

Therefore, d is the correct option, for √6 is an irrational number.

Answer: d. √42/√7

I hope this helps. :D