Question

Pleaseeee..... Who will solve this I will mark them as what you need.....​

Answer 1

Answer:

cos thetha= 12/13

Step-by-step explanation:

Let ∆ABC,

take AB as perpendicular,BC as Base

and AC as hypotenuse

Now, Sin thetha =5/13

i.e Perpendicular=5, Hypotenuse=13

By solving,Base would come as 12

And since, cos thetha=BASE/HYPOTENUSE

Therefore,Cos thetha= 12/13

Answer 2

Answer:

119/169

Step-by-step explanation:

sin x =5/13

then by Pythagoras theorem

cos x=12/13

cos 2x=cos^2-sin^2

(12/13)^2 - (5/13)^2

144/169 - 25/169

cos 2x=119/169