Math, asked by swastikajoshi62, 2 months ago

pleaseeeeeeeee solveeeee​

Attachments:

Answers

Answered by akashmishra12337
1

Answer:

p^2 +q^2= 125

Step-by-step explanation:

p+q=13

squaring both side

(p+q)^2=(13)^2

p^2 +q^2+2pq =169

putting the value of pq

p^2 +q^2+2×22 =169

p^2 +q^2+44=169

p^2 +q^2=169- 44

p^2 +q^2=125

please follow

mark me brainiest

1st wala bhi batana hai kya

Answered by Salmonpanna2022
3

Step-by-step explanation:

a) Question:-

Given:-

a -  \frac{1}{a}  = 4 \\  \\

Find:-

The \:  value \:  of \:  \:  {a}^{2}  +  \frac{1}{ {a}^{2} }  \\  \\

Solution:-

Let's solve the problem,

We have

 {a} -  \frac{1}{a}  = 4 \\  \\

Squaring on both sides, we get

 \bigg(a -  \frac{1}{a}  \bigg)^{2}  = (4 {)}^{2}  \\

✯Using algebraic identity

(x - y)² = (x - y)(x + y) = x² - 2xy + y²

Now,

⟹ {a}^{2}  - 2 \times a \times   \frac{1}{a}   + \bigg( \frac{1}{a} \bigg)^{2}  = 16 \\  \\

⟹ {a}^{2}  - 2  \times \cancel{a} \times  \frac{1}{ \cancel{a}}  +  \frac{1}{ { a}^{2} }  = 16 \\  \\

⟹ {a}^{2}  - 2 +  \frac{1}{ {a}^{2} }  = 16 \\  \\

⟹ {a}^{2}  +  \frac{1}{ {a}^{2} }  = 16 + 2 \\  \\

⟹ {a}^{2}  +  \frac{1}{ {a}^{2} }  = 18 \\  \\

So, the value of a²+1/a² is 18 Ans.

_________________________

b) Question:-

Given, p+q = 13 and Pq = 22

We know that, (p+q)² = p²+q²+2pq _____(1)

By putting the given value in equation (1),

(13)² = p² + q² + 2(22)

169 = p² + q² + 44

169 - 44 = p² + q²

125 = p² + q²

So, the value of p² + q² is 125 Ans.

  • I hope it's help you...☺
Similar questions