pleaseeeeeeeeee solve question with proof
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PQ || RS
therefore angle AEF + BFC = 180 ( co int angls) .....1
triangle AOE is congurent to triangle OEC
therefore angle AEO = OEC
similarly angle BFO = OFC
1/2 AEF + 1/2BFC = 90
OEC + OFC = 90
EOF + OEC + OFC = 180 (angle sum property)
EOF + 90 = 180
EOF = 90
hope this would help u:)
therefore angle AEF + BFC = 180 ( co int angls) .....1
triangle AOE is congurent to triangle OEC
therefore angle AEO = OEC
similarly angle BFO = OFC
1/2 AEF + 1/2BFC = 90
OEC + OFC = 90
EOF + OEC + OFC = 180 (angle sum property)
EOF + 90 = 180
EOF = 90
hope this would help u:)
arnav75:
thank s
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