Question

Pleaseeeeeeeeeeee solve this.​

Answer 1

$\small \tt ❥given \: two \: sets \: A \: and \: B \: have \: 9 \: elements \: in \: common$

$\small \tt we \: know \: that \: n((A \times B)n( B \times A)) \\= n((An B) \times ( BnA))$

$\small \tt \therefore n((A \times B)n( B \times A)) = n((A n B) \times (B nA)) \\ = n(A n B).n(BnA) \\ = n(A n B).n(A n B) \\ = 9 \times 9 = {9}^{2}$

$\tt hence \: option \: \boxed{ \tt 3) \: {9}^{2} is \: ✅}$

Answer 2

Answer:❥given : two sets A and B have 9 elements common ❥given two sets A and B have 9 elements in common

we know that n (A times B)n( B times A)= n((An B) \times ( BnA)

we know that n((A×B)n(B×A))

=n((AnB)×(BnA))

therefore n((A \times B)n( B \times A)) = n((A n B) \times (B nA)) = n(A n B).n(BnA) = n(A n B).n(A n B) = 9 \times 9 = {9}^{2}

∴n((A×B)n(B×A))=n((AnB)×(BnA))

=n(AnB).n(BnA)

=n(AnB).n(AnB)

=9×9=9

2

hence option boxed {9}^{2} ✅}hence option

3)9

2

is✅

Hope it helps...✌✌✌