Question

PleaseHelp
Dina has a mass of 50 kilograms and is waiting at the top of a ski slope that’s 5 meters high.
The maximum kinetic energy she can reach when she skis to the bottom of the slope is
joules.
Use PE = m × g × h and g = 9.8 m/s2. Ignore air resistance and friction.

Answer 1

Answer:

$\huge\mathfrak\purple{answer}$

v = 9.9 m/s. So Dina's maximum velocity on the bottom of the ski slope is v = 9.9 m/s

Answer 2

Answer:

KE(max) = 2450 Joules

Step-by-step explanation:

Dina's at a height (h) = 5 m

Her mass (m) = 50 kg

Velocity at the top of the slope = 0 m/s

Height at the bottom of the slope = 0 m

PE at the top of the ski slope (PE1) = m*g*h = 50*9.8*5 = 2450 Joules.

KE at the top of the ski slope (KE1) = (1/2)*mv² = (1/2)*50*0² = 0 Joules.

PE at the bottom of the slope (PE2) = m*g*h = 50*9.8*0 = 0 Joules

KE at the bottom of the slope (KE2) = (1/2)*mv² = KE(max).

According to the law of conservation of energy,

PE1 + KE1 = PE2 + KE2

2450 + 0 = 0 + KE(max)

KE(max) = 2450 Joules