pleasssssssse answer 12th stdents
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Answer:
12.6A
Explanation:
Given, R = 0.5 ohm ; r = 0.1 ohm ; E = 1.4 volt ; n = 45
Since R>r , connecting the cells in series will give max current.
Effective emf = nE = 45(1.4) = 63V
Effective resistance = nr + R = 45(0.1) + 0.5
= 5 ohm
Current Imax = nE/(nr + R)
Imax = 63/5
Imax = 12.6 A
Hope this helps
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