Question

Pleasw solve this find the equation of the line perpendicular to the linex -2y+3=0 and passing through the point(1,-2) ??????

Answer 1

Heya _____

Please solve this find the equation of the line perpendicular to the line -2y+3=0 and passing through the point(1,-2) ??????

Solution _______

x = 2y+3 = 0

y = 1/x + 3/2

Slope of line one is M1

Slope of line 2 is perpendicular to line 1

So ______

M2 = 1/M1 = -2

y -(-2) = -2(x-1)

so.... y+2x = 0 is the passing point..

Thank you

Answer 2

hope this help you friend