Question

pleave solve using quadratic equation​

Answer 1

$4 \sqrt{ 3}y ^{2} + 5y - 2 \sqrt{3 = 0}$

$4 \sqrt{3} y ^{2} + (8 - 3)y - 2 \sqrt{3} = 0$

$4 \sqrt{3} y ^{2} + 8y - 3y - 2 \sqrt{3} = 0$

$4y( \sqrt{3} y + 2) - \sqrt{3} ( \sqrt{3}y + 2)$

$( \sqrt{3} y + 2)(4y - \sqrt{3}) = 0$

$either$

$\sqrt{3} y + 2 = 0$

$y = \frac{ - 2}{ \sqrt{3} }$

$or$

$4y - \sqrt{3} = 0$

$y = \frac{ \sqrt{3} }{4}$

Answer 2

Answer:

Step-by-step explanation:

JAI mahakal .

Check in the attachment....Ram ram.