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Answers
Answer:
1.distance between city c to e
C toD + D to E
=85000+7850
=92850
convert it into km
92850÷1000
=92.85km
2. distance between city A to D
45km+9000cm+85000m
convert 45km into m
45×1000
=45000
convert 9000cm into m
9000÷100
=90m
45000+90+85000
=1, 30,090m
distance between city b to e
9000cm+85000m+7850m
convert 9000cm into m
so, 90+85000+7850
=92, 940
therefore, route B to E is the shorter
3.distance between city C to A in mm
45km +9000cm
convert 45km into mm
=45000000mm
convert 9000cm to mm
=90000mm
45000000+90000
=45090000mm
Answer:
(i) C to E = C to D + D to E =
85000m + 7850 m =
92850m to km =
92.85 km
(ii) A to D = A to B + B to C + C to D =
45000 m + 90 m + 85000 m
89,590 m
B to E = B to C + C to D + D to E =
90 m + 85000 m + 7850
89590 < 92940
(iii) C to A = A to B + B to C =
45000000 mm + 90000 mm
45,090,000 mm
hope it helps you
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