Math, asked by visharad19, 14 hours ago

Pleaze tell the solution

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Answered by jerinaxavier0
0

Answer:

1.distance between city c to e

C toD + D to E

=85000+7850

=92850

convert it into km

92850÷1000

=92.85km

2. distance between city A to D

45km+9000cm+85000m

convert 45km into m

45×1000

=45000

convert 9000cm into m

9000÷100

=90m

45000+90+85000

=1, 30,090m

distance between city b to e

9000cm+85000m+7850m

convert 9000cm into m

so, 90+85000+7850

=92, 940

therefore, route B to E is the shorter

3.distance between city C to A in mm

45km +9000cm

convert 45km into mm

=45000000mm

convert 9000cm to mm

=90000mm

45000000+90000

=45090000mm

Answered by studiesarebest10
2

Answer:

(i) C to E = C to D + D to E =

85000m + 7850 m =

92850m to km =

92.85 km

(ii) A to D = A to B + B to C + C to D =

45000 m + 90 m + 85000 m

89,590 m

B to E = B to C + C to D + D to E =

90 m + 85000 m + 7850

89590 < 92940

(iii) C to A = A to B + B to C =

45000000 mm + 90000 mm

45,090,000 mm

hope it helps you

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