Question

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Answer 1

Answer:

Given 

tan 20 = k----(1)

tan 250 = tan (270-20) = cot 20 = 1/tan 20 = 1/k

tan 340 = tan(360-20) = - tan 20 = -k

tan 200 = tan (180+20) = tan 20 =k

tan 110 = tan (90+20 ) = -cot 20 = -1/tan 20 = -1/k

(tan 250 +tan 340) /( tan200 -tan 110)

= (1/k -k)/(k + 1/k)

= (1 -k²)/ (k²+1)

4) is correct

Answer 2

Answer:

hope you understand

Step-by-step explanation:

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