Question

plese answer me......​

Answer 1

compare the powers given the equation as the base is same.

by comparing you'll get :-

3 + (-6) = 2m-1

=> -3 = 2m-1

=> 1-2m = 3

=> -2m = 2

=> m = -1

^_^

Answer 2

Answer:

Step-by-step explanation:

$\Large\underline{\rm \purple{Solution}}:\\\\\sf \small \longrightarrow \left(\dfrac{2}{9}\right)^3 \times \left(\dfrac{2}{9}\right)^{-6} = \left(\dfrac{2}{9}\right)^{2m-1}\\\\\\\rm Using\; \bf a^m\times a^{-n} = a^{m-n}\\\\\\\sf \small\longrightarrow \left[\:\dfrac{2}{9}\:\right]^{3-6} = \left[\dfrac{2}{9}\right]^{2m-1}\\\\\\\rm Using \; \bf a^m = a^m \implies m= n\\\\\\ \sf \small \longrightarrow - 6 = 2m - 1\\\\\\\sf \small \longrightarrow -6+1 = 2m \\\\\\ \bf \longrightarrow\red{ \dfrac{5}{2}} = m$$\\\\\\\underline{\bf\green{More \;information :}} \\\\\\ \boxed{\begin{minipage}{6cm} \sf \underline{Some important identities}:\\\\ \bullet\; \sf (a+b)^2 = a^2 + b^2 + 2ab\\\\\bullet \sf \:(a-b)^2 = a^2 + b^2 - 2ab\\\\\bullet\:\sf a^2 + b^2 = (a + b)^2 - 2ab \\\\\bullet \sf \: a^2 - b^2 = (a + b)(a-b)\end{minipage}}$