Question

Plese answer of 1st Question

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Let  us assume √3 is a rational no.

√3=a/b ,where b≠0 HCF(a,b)=1

squaring on both sides

3=a²/b²

a²=3b² ...... Eq1

3 divides a²

3 divides a

a=3c (c for some integer) ......Eq2

substituing Eq2 in Eq1

9c²=3b²

3c²=b² ÷3

3 divides b²

3 divide b

∴3 divides both a and b

∴HCF(a,b)=3

But given HCF(a,b)=1

Therefore This is a contradiction to our assumption

∴√3 is an irrational no.

5+√3 is also irrational ∵RATIONAL+IRRATIONAL=IRRATIONAL