Math, asked by sahasraattipalli, 8 months ago

plese answer this question i will make you brainliest with procedure​

Attachments:

Answers

Answered by amitsnh
0

Answer:

= x^(b - c)(b + c) * x^(c - a)(c + a) * x^(a - b)(a + b)

= x^(b^2 - c^2) * x^(c^2 - a^2) * x^(a^2 - b^2)

= x^(b^2 - c^2 + c^2 - a^2 + a^2 - b^2)

= x^0

= 1

Similar questions