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Answer 1

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Now, from the table, it can be observed that n = 60

=> 45 + x + y = 60

=> x + y = 60 - 45

=> x + y = 15 ...........1

Given, median of the data is 28.5 which lies in the interval 20-30

Therefore, median class = 20-30

Lower limit(l) of median class = 20

Cumulative frequency(cf) of class preceding the median class = 5 + x

Frequency of the median class = 20

Class sixze(h) of median class = 10

Now, Median = l + {(n/2 - cf)/f} * h

=> 28.5 = 20 + [{60/2 - (5 + x)}/20] * 10

=> 28.5 = 20 + {(30 - 5 - x)/20} * 10

=> 28.5 = 20 + {(25 - x)/20} * 10

=> 28.5 = 20 + (25 - x)/2

=> 28.5 * 2 = 20 * 2 + 25 - x

=> 57 = 40 + 25 - x

=> 57 = 65 - x

=> x = 65 - 57

=> x = 8

From the equation 1, we get

=> 8 + y = 15

=> y = 15 - 8

=> y = 7

So, the value of x = 8 and y = 7