English, asked by Aasthachauhan, 1 year ago

plese answr this qus fast

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Answered by ritvikjain2090ow0ydl
1
hello,
LHS=
tan(45°+x)

(tan45°+tan45°)/(1-tanx·tan45°)

(tanx+1)(1-tanx)

(sinx/cosx+1)/(1-sinx/cosx)

(sinx+cosx)/(cosx-sinx)

(sinx+cosx)(cosx-sinx)/(cosx-sinx)²

(sin²x-cos²x)/(1-sin2x)

(cos2x)/(sin2x-1)

1/sin2x-1/cos2x

1/sin2x/cos2x-1/cos2x

1/tan2x-1sec2x

tan2x+sec2x
=RHS
hope this helps,if u like it please mark it as brainliest
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