Physics, asked by naishrahgajkandh, 8 months ago

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Answered by Anonymous
7

Answer:

1.) Newton's second law, which states that the force F acting on a body is equal to the mass m of the body multiplied by the acceleration a of its centre of mass, F = ma, is the basic equation of motion in classical mechanics.

Force, F = Mass, m × Acceleration, a

➡ F = ma

The three general equations of motion are :

➡ v = u + at

➡ s = ut + (1/2) × at^2

➡ v^2 = u^2 + 2as

2.) First general equation of motion :

v = u + at

Derivation :-

Let consider a body moving with initial velocity u, constant acceleration a, time t and final velocity v.

Then,

We know that,

Acceleration = Change of velocity/Time taken

➡ a = (v - u) /t

➡ at = v - u

➡v = u + at

Hence, derived.

3.) Third equation of motion :

S = ut + 1/2 × at^2

Derivation :-

Let the Displacement covered by the body be 'S' whose initial velocity is 'u', final velocity is 'v' and time taken is 't'.

Then, given,

➡ Displacement = S

➡ Initial Velocity = u

➡ Final Velocity = v

➡ Time taken = t

We know that,

Displacement = Average Velocity × Time ....... (i)

And, Average Velocity = (Initial Velocity + Final Velocity) / 2 ....... (ii)

By applying the values, of equation (ii) in equation (i), we get,

➡ Displacement = {(Initial Velocity + Final Velocity) / 2} × t

Let us apply now the symbols of this equation,

➡ S = { (u + v) / 2 } × t

..... (iii)

First equation of motion :

v = u + at

By applying the value 'v' from the First of equation of motion in the equation (iii), we get,

➡ S = { (u + u + at) / 2 } × t

➡ S = { (2u + at) / 2 } × t

➡ S = [ (2u / 2) + (at / 2) ] × t

➡ S = [ u + (at / 2) ] × t

➡ S = ut + (at^2) / 2

➡ S = ut + (1/2) × at^2

In this way, we derive the third equation of motion.

Hence, proved.

4.)

➡ The principle is that the slope of the line on a velocity-time graph reveals useful information about the acceleration of the object. If the acceleration is zero, then the slope is zero (i.e., a horizontal line). If the acceleration is positive, then the slope is positive (i.e., an upward sloping line).

➡ Velocity-time graphs are used to describe the motion of objects which are moving in a straight line. They can be used to show acceleration and to work out displacement.

➡ The slope of a velocity graph represents the acceleration of the object. So, the value of the slope at a particular time represents the acceleration of the object at that instant.

Answered by tanishachauhan70
0

Answer:

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