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i. 1/25
ii. 9
iii. -3
Hope this helps you!!
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ii. 9
iii. -3
Hope this helps you!!
Please mark as brainliest!
Answered by
2
(i) p³ = (5²)⁻³
p³ = 1/(5²)³ (as a⁻ⁿ = 1/aⁿ)
p = ∛1/∛(5²)³
p = 1/5²
p = 1/25
(ii) (4/7)¹² ÷ (4/7)^p = 64/343
(4/7)^p = (4/7)¹² ÷ (4/7)³ (as 4³ = 64 and 7³ = 343)
(4/7)^p = (4/7)¹² × (7/4)³
(4/7)^p = (4/7)¹²⁻³ (as aⁿ/aˣ = aⁿ⁻ˣ)
(4/7)^p = (4/7)⁹
Taking only powers
p = 9
(iii)(((-3/7)⁻²)³)^p = (-7/3)⁻¹⁸
(-3/7)-⁶^p = (-3/7)¹⁸ (as a⁻ⁿ = 1/aⁿ)
Taking omly powers
-6p = 18
p = -3
:)(: Hope this Helps !!! :)(:
p³ = 1/(5²)³ (as a⁻ⁿ = 1/aⁿ)
p = ∛1/∛(5²)³
p = 1/5²
p = 1/25
(ii) (4/7)¹² ÷ (4/7)^p = 64/343
(4/7)^p = (4/7)¹² ÷ (4/7)³ (as 4³ = 64 and 7³ = 343)
(4/7)^p = (4/7)¹² × (7/4)³
(4/7)^p = (4/7)¹²⁻³ (as aⁿ/aˣ = aⁿ⁻ˣ)
(4/7)^p = (4/7)⁹
Taking only powers
p = 9
(iii)(((-3/7)⁻²)³)^p = (-7/3)⁻¹⁸
(-3/7)-⁶^p = (-3/7)¹⁸ (as a⁻ⁿ = 1/aⁿ)
Taking omly powers
-6p = 18
p = -3
:)(: Hope this Helps !!! :)(:
nitthesh7:
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