plese help me to solve question no. 11th and 12th. It's argent
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Ques. no. 11:- value of a=66a°+56a°+27a°+31a°=360°
= 180a=360°
= a=360°-180°
= a=180°
Hence, a=180°
= 180a=360°
= a=360°-180°
= a=180°
Hence, a=180°
aryangupta50:
OK... ur answer is correct,let's check it =put a=2 then 66x2+56x2+27x2+31x2=360°
it's my mistake...
ok
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Q11-66a+56a+27a+31a=360
180a=360
a=360/180
a=2
Q12-
180a=360
a=360/180
a=2
Q12-
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