plese solve area of this trapezium
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Answer:
168 cm^2
Step-by-step explanation:
area = a+b/2 * h
now in trapezium EDFC,
DC = 17 - 8 = 9 cm
h = 6 cm
a=8 cm
b= 9 cm
area = 8+9/2 * 6
=17/2 * 6
=17 * 3
= 51 cm^2
now in trapezium DCAB,
a=17 cm
b=9 cm
h= 9
area = 17+9/2 * 9
=26/2 * 9
= 13 * 9
= 117 cm^2
.'. total area = area of EFDC + area of DCAB
= 51 + 117
= 168 cm^2
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