Question

plese solve both of quest 11​

Answer 1

The second Question is not clear

Answer 2

Answer:

9√15 cm^2

Step-by-step explanation:

11 .

Let the third side of this triangle be x.

Perimeter of triangle = 30 cm

12 cm + 12 cm + x = 30 cm

x = 6 cm

s = Perimeter of triangle/2 = 30cm/2 = 15cm

By Heron’s formula,

= √ (s)(s - a)(s-b)(s-c)

= [√ (15)(15 - 12)(15-12)(15-6) ] cm^2

= [ √ (15) (3) (3) (9) ] cm^2

= 9√15 cm^2

                                                                                                                             

OR

P of eq. triangle = 3 × side

side = 162/3 = 54cm

a = b = c= 54

s = 162 / 2= 81

By Heron’s formula,

= √ (s)(s - a)(s-b)(s-c)

= √ 81 (81-54) (81-54) (81-54)

= 9√27*27*27

= 9*27*3√3

= 1261.17 cm^2

hope it helps