plese solve the ouestion
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∠PQR+ext.∠Q=180
∘
[Linear pair]
∠PQR+80
∘
=180
∘
⇒∠PQR=100
∘
x+100
∘
=180
∘
[Supplementary angles of parallelogram]
x=80
∘
In △PSR, Z=∠SRP [Alternate angles]
∴80
∘
+60
∘
+Z=180
∘
⇒Z=180
∘
−140
∘
=40
∘
In △PQR,
40
∘
+y+100
∘
=80
∘
y=180
∘
−140
∘
=40
∘
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